设点P坐标为(p,p+m),p∈R|PA|=|PB|/24|PA|^2=|PB|^24[(p-1)^2+(p+m)^2]=(p-4)^2+(p+m)^24(p-1)^2-(p-4)^2=-3(p+m)^23p^2-20=-3p^2-6mp-3m^26p^2+6mp+3m^2-20=0因为p∈R,所以判别式△=36m^2-24(3m^2-20)>=0-36m^2+480>=0m^2<=40/3(-2/3)*√30<=m<=(2/3)*√30